If board02 is empty or an O, my streak ends at 2, which is not a winning streak.Hello team, I have this assignment to do: Quote: Have you ever played Connect 4 Its a popular kids game by the Hasbro company.
In this project, your task is create a Connect 4 game in Python. Youll want to draw the board, and allow two players to take turns placing their pieces on the board (but as you learned above, they can only do so by choosing a column, not a row). The first player to get 4 across or diagonal should win Normally the pieces would be red and black, but you can use X and O instead. Verify if there is 4 across or diagonal to end the game So far I just manage to come up with the first step, it looks like that. Firstly I want to make the function add an X or O to the bottom row, or the 8th row, of the column the user input. I would use a list of lists to make your 4x4 grid and separate the logic from the display. I would also define a function to display the grid, doing input-logic-display with the logic part also checking to see if there is a winner. Hi, By coincidence I wrote a Connect 4 game the other day, a textual version and a GUI Tkinter version. Define a 2D matrix, play the game in memory, and print the whole matrix after each move. The hardest part is to validate if there is a winner, vertically, horizontally (and oblique) Paul. Team, I managed to add user input as I wanted, by stacking them according to the column the users choose. I like gravity to play its role, coins drop to the lowest position possible vertically (like in a real game) So the user only needs to enter a column of choice (x-axis), the y value is automatically determined by how many coins are already in that column. A user entry is an x,y element in your 2D list (matrix) that turns into an X or an O. Then you need 3 validation routines that loop over the matrix: -one that counts how many of the same are on each row (adjacent) -in each column -and diagonally (a bit more tricky index-wise) If one of the counts gets to 4, you have a winner. Paul. A spot may be empty or it may be held by player 1 or player 2. ![]() I chose two because I want X to b zero, O to be one, and empty to be something else. By making them 0, 1, 2 I can make a list of markers to use when drawing the board. X play 1.8: When X enters 2 as her play, the board will look like this: Output: X. O play 1.8: Finding the winner is the most difficult part of the program, but there is an obvious, brute force method that is easy to write and fairly straight forward. You have to think about how you would find the winner in connect 4 if you were limited to only looking at one cell at a time. Remember that only the last player can win, so you only have to check for 4 Xs or 4 Os in a row, not both.
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